CBSE Class 12-science Answered
Please solve Q no 16
Asked by Nishantthakre95 | 15 Sep, 2019, 05:53: AM
Expert Answer
Initially capacitors C1 and C2 are charged in the loop ABEF , before switch S is closed.
By considering capacitance of C1 and C2 are 2μF and by applying Kirchoff's voltage law for the loop ABEF ,
we have, -10 + [q / (2×10-6)] -10 + [q / (2×10-6)] = 0
Hence charge on each of capacitors C1 and C2 , q = 20 × 10-6 C
Hence potential across each capacitance = q/C = 20 × 10-6 / 2× 10-6 = 10 V
When switch is closed, capacitor C3 is charged in the loop BGDE.
By Kirchoff's voltage in the loop BGDE, -20 + [q / (2×10-6)] -10 = 0
Hence charge on capacitor C3 , q = 60× 10-6 C
To charge the capacitors, workdone by battery, q × V = 60× 10-6 × 20 = 1200 μJ
Energy stored in capacitor = (1/2)CV2 = (1/2)×2× 10-6 × 30 × 30 = 900 μJ
Heat energy produced in the circuit = (1200 - 900 ) μJ = 300 μJ = 0.3 mJ
Answered by Thiyagarajan K | 15 Sep, 2019, 12:28: PM
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