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Please solve both questions

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Asked by Vidya 10th March 2018, 8:38 PM
Answered by Expert
Answer:
Radiation power loss = εAσ(T4 - Tc4) , where ε is emissivity of the surface, A is area of surface, σ is stefan-boltzman constant, T is the radiating body temperature in kelvin, Tc is temperature of surroundings in kelvin. We consider Radiation power loss is proportional to (T4 - Tc4).
In first case we take mean temperature 90ºC or 363 K and Radiation loss P1 is proportioanal to (3634-2934)
In second case we take mean temperature 70ºC or 343 K and Radiation loss P2 is proportioanal to (3434-2934)
 
begin mathsize 12px style P subscript 2 over P subscript 1 equals space fraction numerator open parentheses 343 to the power of 4 space minus space 293 to the power of 4 close parentheses over denominator open parentheses 363 to the power of 4 space minus space 293 to the power of 4 close parentheses end fraction space equals space 0.65 h e n c e space i n space s e c o n d space c a s e space t i m e space t a k e n space t o space c o o l space i s space 0.65 cross times 120 space equals space 78 space s e c o n d s end style

Answered by Expert 10th March 2018, 11:03 PM
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