Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/ICSE/Class 12 Science/Physics

Please solve

qsnImg
Asked by Amuwadunsin 26th February 2020, 2:31 PM
Answered by Expert
Answer:
For m2 , we have,  m2g - T = m2 a .......................(1)
For m1 , we have ,    T  = m1 a  .....................(2)
 
Where T is tension in the string and a is acceleration of system.
 
By adding (1) and (2),  we get  a =  [ m2 / ( m1 + m2 ) ] g  ......................(3)
 
If m1 starts from rest and travel a distance d in t seconds with acceleration a,
 
then d = (1/2) a t2 ,  or   t = ( 2d / a )1/2 = [ 2d (m1 + m2 ) / ( m2 g ) ]1/2 
---------------------------------------------------------------
for block of mass m1 , we have ,  T - ( m1 g )= m1 a ......................(1)
 
for block of mass m2 , we have ,  ( m2 g ) - T = m2 a ...................(2)
 
Where T is tension in the string and a is acceleration of system.
 
By adding both eqn. above , we get ,  a  = [ ( m2 - m1 ) / ( m1 + m2 ) ] g
 
If mass m2 hitting the ground after travelling a distance x starting from rest,
 
we have v2 = 2 a x  ,   where v is final speed when m2 is hitting the ground
 
hence v = { 2 [ ( m2 - m1 ) / ( m1 + m2 ) ] g x }1/2
Answered by Expert 27th February 2020, 9:30 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Tags: single-fixed-pulley-system
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

explain abt pulleys
18th February 2023, 2:26 PM
RELATED STUDY RESOURCES :
ICSE Class-12-science QUESTION ANSWERS

Chat with us on WhatsApp