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CBSE Class 11-commerce Answered

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Asked by deepakagarwal1024 | 05 Jan, 2019, 10:52: AM
answered-by-expert Expert Answer
Let f(x) = x3 - 2x2 -6x +9find
put x= 1 and we find f(1)≠ 0, hence (x-1) is not a factor
put x = -1 , we find f(-1) ≠ 0, hence (x+1) is  nota factor
 
like this we try for x= 2, and x=-2, we will find (x+2) and (x-2) are not factor
 
put x = 3 , we find f(3) = 0, hence (x-3) is  a factor
 
if we divide f(x) by (x-3), we get (x2 +x -3) is a quotient
 
(x2 +x -3) is quadratic equation and is factorised as begin mathsize 12px style open parentheses x plus p close parentheses left parenthesis x minus q right parenthesis space w h e r e space p space equals space fraction numerator negative 1 plus square root of 13 over denominator 2 end fraction space a n d space q space equals space fraction numerator negative 1 minus square root of 13 over denominator 2 end fraction end style
Answered by Thiyagarajan K | 06 Jan, 2019, 07:56: AM
CBSE 11-commerce - Accountancy
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BRS
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Asked by tussharpoddar7 | 08 Jul, 2020, 11:30: PM
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CBSE 11-commerce - Accountancy
plz
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CBSE 11-commerce - Accountancy
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