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Asked by ayushvishodiya112 25th June 2019, 7:29 PM
Answered by Expert
Answer:
_ _ _ _
total number of codes ending with even numbers = 432K
that is
for first position you have 21 consonants = 21 ways
for second position you have 20 (distinct) = 20 ways
for third you have 9 digits = 9 ways
for fourth (even numbers 2, 4, 6, 8) = 4 ways
Answered by Expert 26th June 2019, 9:30 AM
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