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Asked by ayushvishodiya112 | 25 Jun, 2019, 07:29: PM
Expert Answer
_ _ _ _
total number of codes ending with even numbers = 432K
that is
for first position you have 21 consonants = 21 ways
for second position you have 20 (distinct) = 20 ways
for third you have 9 digits = 9 ways
for fourth (even numbers 2, 4, 6, 8) = 4 ways
Answered by Arun | 26 Jun, 2019, 09:30: AM
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