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G i v e n space limit as x rightwards arrow 1 of f left parenthesis x right parenthesis equals 2 space comma space limit as x rightwards arrow 1 of g left parenthesis x right parenthesis equals 3 space comma space limit as x rightwards arrow 1 of h left parenthesis x right parenthesis equals 2
f i n d space t h e space v a l u e space o f limit as x rightwards arrow 1 of open parentheses fraction numerator g left parenthesis x right parenthesis over denominator f left parenthesis x right parenthesis minus h left parenthesis x right parenthesis end fraction close parentheses

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Asked by Topperlearning User 16th November 2016, 1:28 AM
Answered by Expert
Answer:

space limit as x rightwards arrow 1 of f left parenthesis x right parenthesis equals 2 space comma space limit as x rightwards arrow 1 of g left parenthesis x right parenthesis equals 3 space comma space limit as x rightwards arrow 1 of h left parenthesis x right parenthesis equals 2
limit as x rightwards arrow 1 of open parentheses fraction numerator g left parenthesis x right parenthesis over denominator f left parenthesis x right parenthesis minus h left parenthesis x right parenthesis end fraction close parentheses
equals fraction numerator limit as x rightwards arrow 1 of g left parenthesis x right parenthesis over denominator stack lim left square bracket with x rightwards arrow 1 below f left parenthesis x right parenthesis minus h left parenthesis x right parenthesis right square bracket end fraction
equals fraction numerator 3 over denominator 2 minus 2 end fraction equals infinity
S o space t h e space l i m i t space d o e s n apostrophe t space e x i s t

Answered by Expert 16th November 2016, 3:28 AM
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