ICSE Class 8 Answered

$Multiply space space 2 straight x squared minus 3 straight x plus 1 space by space minus 3 straight x squared minus 4 straight x plus 2 space using space column space method.$ Please provide solution to this question

Asked by Topperlearning User | 16 Sep, 2016, 03:43: PM

Expert Answer

$space space space 2 straight x squared minus 3 straight x plus 1 minus 3 straight x squared minus 4 straight x plus 2 minus negative negative negative negative negative negative negative negative minus 6 straight x to the power of 4 plus 9 x cubed minus 3 x squared space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left square bracket Multiply space first space polynomial space by space minus 3 straight x squared right square bracket space space space space space space space space space minus 8 x cubed plus 12 x squared minus 4 x space space space space space space space space space space space space space space space space space space space space space space space left square bracket Multiply space first space polynomial space by space minus 4 x right square bracket space space space space space space space space space space space space space space space space space space space space plus space 4 x squared minus 6 x plus 2 space space space space space space space space space space space space space space space space space left square bracket Multiply space first space polynomial space by space 2 right square bracket minus negative negative negative negative negative negative negative negative negative negative negative negative negative minus 6 straight x to the power of 4 plus x cubed plus 13 x squared minus 10 x plus 2 space space space space space space space space space space space space space space space space space space space left square bracket This space is space the space required space product. right square bracket minus negative negative negative negative negative negative negative negative negative negative negative negative negative$