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Home / Doubts and Solutions/JEE/Physics

please olve the question

Asked by jaychandran1967 28th November 2017, 12:08 PM
Answered by Expert
Answer:
Path of one projectile as seen by an observer on another projectile is
 
begin mathsize 16px style f o r m u l a space f o r space p a t h space o f space t h e space p r o j e c t i l e s equals u cos theta minus fraction numerator g t squared over denominator 2 end fraction p a t h space o f space p r o j e c t i l e space o n e space s subscript 1 equals u subscript 1 cos theta subscript 1 t i minus fraction numerator g t squared over denominator 2 end fraction j p a t h space o f space p r o j e c t i l e space t w o space s subscript 2 equals u subscript 2 cos theta subscript 2 t i minus fraction numerator g t squared over denominator 2 end fraction j p a t h space o f space p r o j e c t i l e space o n e space w. r. t space t w o s subscript 2 minus s subscript 1 equals u subscript 2 cos theta subscript 2 t i minus fraction numerator g t squared over denominator 2 end fraction j space space space minus space open parentheses u subscript 1 cos theta subscript 1 t i minus fraction numerator g t squared over denominator 2 end fraction j close parentheses space plus 0 j space s subscript 2 minus s subscript 1 equals left parenthesis u subscript 2 cos theta subscript 2 space space minus space u subscript 1 cos theta subscript 1 right parenthesis t i space plus space 0 j space space w h i c h space i s space o f space t h e space f o r m space o f space x i plus y j w h i c h space i s space a space s t r a i g h t space l i n e end style
Answered by Expert 28th November 2017, 2:41 PM
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