CBSE Class 11-science Answered
Please help me with this question
Asked by | 19 Apr, 2010, 10:05: AM
Expert Answer
Using the following result,we can write,
tan(C+D) = (tanC + tanD)/(1 - tanC tanD)
tan2A = [tan(A+B) + tan(A-B)]/(1 - tantan(A+B) tan(A-B)) = (x+y)/(1 - xy)
Similarly,
tan2B = [tan(A+B) - tan(A-B)]/(1 + tan(A+B) tan(A-B)) = (x-y)/(1 + xy)
Regards,
Team,
TopperLearning.
Answered by | 19 Apr, 2010, 01:53: PM
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