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Asked by akshitaasia 19th March 2018, 11:04 AM
Answered by Expert
Answer:
begin mathsize 16px style Let space top enclose straight a equals 2 straight i with hat on top minus straight j with hat on top minus straight k with hat on top space and space straight b with bar on top equals straight i with hat on top plus 2 straight j with hat on top plus straight k with hat on top
Projection space of space top enclose straight a space in space the space direction space of space straight b with bar on top
is space
equals fraction numerator straight a with bar on top times straight b with bar on top over denominator open vertical bar straight b with bar on top close vertical bar end fraction
equals fraction numerator open parentheses 2 straight i with hat on top minus straight j with hat on top minus straight k with hat on top close parentheses times open parentheses straight i with hat on top plus 2 straight j with hat on top plus straight k with hat on top close parentheses over denominator square root of 1 squared plus 2 squared plus 1 to the power of 1 end root end fraction
equals fraction numerator 2 cross times 1 plus open parentheses negative 1 close parentheses cross times 2 plus open parentheses negative 1 close parentheses cross times 1 over denominator square root of 1 plus 4 plus 1 end root end fraction
equals fraction numerator 2 minus 2 minus 1 over denominator square root of 6 end fraction
equals fraction numerator negative 1 over denominator square root of 6 end fraction end style
Answered by Expert 19th March 2018, 11:24 AM
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