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CBSE Class 11-science Answered

please help along with me...
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Asked by nitishkrnehu09 | 06 Feb, 2018, 09:20: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight X plus straight Y plus straight Z equals straight pi fraction numerator straight X plus straight Y plus straight Z over denominator 2 end fraction equals straight pi over 2 fraction numerator straight X plus straight Y over denominator 2 end fraction equals straight pi over 2 minus straight Z over 2 tan open parentheses straight X over 2 plus straight Y over 2 close parentheses equals tan open parentheses straight pi over 2 minus straight Z over 2 close parentheses fraction numerator tan straight X over 2 plus tan straight Y over 2 over denominator 1 minus tan straight X over 2 cross times tan straight Y over 2 end fraction equals cot straight Z over 2 fraction numerator tan straight X over 2 plus tan straight Y over 2 over denominator 1 minus tan straight X over 2 cross times tan straight Y over 2 end fraction equals fraction numerator 1 over denominator tan straight Z over 2 end fraction tan straight Z over 2 open parentheses tan straight X over 2 plus tan straight Y over 2 close parentheses equals 1 minus tan straight X over 2 cross times tan straight Y over 2 Simplifying space we space get space required space equation. end style
Answered by Sneha shidid | 07 Feb, 2018, 09:35: AM

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CBSE 11-science - Maths
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