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CBSE Class 12-science Answered

Please give me the complete solution of 
Asked by Balbir | 23 Oct, 2017, 08:53: PM
answered-by-expert Expert Answer
begin mathsize 16px style integral fraction numerator open parentheses straight a to the power of straight x plus straight b to the power of straight x close parentheses squared over denominator straight a to the power of straight x straight b to the power of straight x end fraction dx
integral open parentheses fraction numerator straight a to the power of 2 straight x end exponent plus 2 straight a to the power of straight x straight b to the power of straight x plus straight b to the power of 2 straight x end exponent over denominator straight a to the power of straight x straight b to the power of straight x end fraction close parentheses dx
integral open parentheses fraction numerator straight a to the power of 2 straight x end exponent over denominator straight a to the power of straight x straight b to the power of straight x end fraction plus fraction numerator 2 straight a to the power of straight x straight b to the power of straight x over denominator straight a to the power of straight x straight b to the power of straight x end fraction plus fraction numerator straight b to the power of 2 straight x end exponent over denominator straight a to the power of straight x straight b to the power of straight x end fraction close parentheses dx
integral open parentheses straight a to the power of straight x over straight b to the power of straight x plus 2 plus straight b to the power of straight x over straight a to the power of straight x close parentheses dx
integral open square brackets open parentheses straight a over straight b close parentheses to the power of straight x plus 2 plus open parentheses fraction numerator begin display style straight b end style over denominator begin display style straight a end style end fraction close parentheses to the power of straight x close square brackets dx
Using space integral straight a to the power of straight x dx space equals space fraction numerator straight a to the power of straight x over denominator log begin display style straight a end style end fraction plus straight c space integrate space further. end style
Answered by Sneha shidid | 14 Dec, 2017, 04:59: PM
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