1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

# PLEASE EXPLAIN STEP-BY-STEP:

Asked by 13th February 2009, 12:54 PM

standrad eqn of ellipse is X2/a2 + Y2 / b2 = 1    compairing with above eqn. we get a = 2 and b = 3

as b>a so  ellipse has y axis as major axis  and  length of major axis is 2b = 6  and length of mionr axis is 2a = 4

eccentricity   as we know a2 = b2 (1-e2)   putting values of a and b we get e =  5 / 3

so focii are  (0,be) and (0,-be)  which is (0,5) and (0, -5)

Answered by Expert 13th February 2009, 7:13 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

### Free related questions

17th October 2016, 11:39 AM
20th October 2016, 12:56 PM
13th November 2016, 11:25 PM
RELATED STUDY RESOURCES :
CBSE Class-11-science QUESTION ANSWERS

### Latest Questions

CBSE X Chemistry
Asked by saradamahapatra9999 21st February 2019, 1:27 PM
CBSE X Social Studies
Asked by Praneeth.june6 21st February 2019, 1:19 PM
CBSE X Social Studies
Asked by Praneeth.june6 21st February 2019, 1:16 PM