Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

PLEASE EXPLAIN STEP-BY-STEP:

Asked by 13th February 2009, 12:54 PM
Answered by Expert
Answer:

standrad eqn of ellipse is X2/a2 + Y2 / b2 = 1    compairing with above eqn. we get a = 2 and b = 3

as b>a so  ellipse has y axis as major axis  and  length of major axis is 2b = 6  and length of mionr axis is 2a = 4

eccentricity   as we know a2 = b2 (1-e2)   putting values of a and b we get e =  5 / 3

so focii are  (0,be) and (0,-be)  which is (0,5) and (0, -5)

Answered by Expert 13th February 2009, 7:13 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Chat with us on WhatsApp