NEET Class neet Answered
Please explain how to do this
Asked by 22bakugoku | 21 Apr, 2019, 05:23: PM
Expert Answer
Latent heat of ice =m×l 100×80=8000 cal
Latent heat of steam =m×l =10×540 = 5400cal
Latent Heat of ice is greater than steam
Specific heat of steam = 10× 1×100 = 1000 cal
Net heat released by steam = 5400+1000= 6400 cal
Latent heat of ice is greater than steam.
So only 6400 cal equivalent of ice gonna melt
So mass of melted ice (water will still be at 0 celcius) = 6400/80 = 80gm
So 80gm of ice will melt into water
Net water = 80 +10(steam) = 90gm
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