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ICSE Class 10 Answered

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Asked by ayush421301 | 27 Feb, 2020, 11:06: PM
answered-by-expert Expert Answer
angle CBQ = angle ABP... veritcally opposite angles
angle DAB is exterior angle of triangle ABP
angle DAB = a + 48
also similarlty
angle DCB = 48 + b
now DABC is cyclic quadrilateral
hence
angle DAB + angle DCB = 180
a + 48 + 48 + b = 180
2b + b = 84
b = 28
a = 14
Answered by Arun | 29 Feb, 2020, 09:47: PM

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