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ICSE Class 10 Answered

Please Answer with reference to Gay Lussac's Law:-   10 litres of propane[C3H8][60%] and Butane[C4H10][40%] is burnt. Calculate the total volume of carbon dioxide formed. Combustion reactions of the mixture are represented as - C3H8 + 5O2 -----> 3CO2 + 4H2O 2C4H10 + 13O2 --------> 8CO2 + 10H2O
Asked by vprincesolomon07 | 07 Aug, 2018, 11:12: PM
answered-by-expert Expert Answer

C3H8 + 5O2 → 3CO2 + 4H2O

2C4H10 + 13O2 → 8CO2 + 10H2O

60 ml of propane (C3H8) gives 3 X 60 = 180 ml CO2

40 ml of butane (C4H10) gives = 8 X 40/2 = 160 ml of CO2

Total carbon dioxide produced = 340 ml

So, when 10 litres of the mixture is burnt = 34 litres of CO2 is produced.

Answered by Ramandeep | 08 Aug, 2018, 11:11: AM

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