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please answer this

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Asked by Prashant DIGHE 7th December 2019, 10:22 PM
Answered by Expert
Answer:
Let the wire bent 90° be on the y and x-axis as shown in figure.
 
Let P be the point on z-axis at a distance 35 cm from bend point of wire.
 
At point P, we have magnteic flux density Bx due to wire lying on y-axis .
 
Similarly we have magnetic flux density By due to wire lying on x-axis.
 
| Bx | = | By | =  μo i / (4π × 0.35 )  = (1/7) × 10-6 T
 
Resutant magnetic flux density = { Bx2 + By2 }1/2 = ( √2/7 )× 10-6 T ≈ 2 μT
Answered by Expert 8th December 2019, 4:05 PM
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