Please answer this
Asked by Prashant DIGHE
20th October 2019,
7:29 AM
Answered by Expert
Answer:
If Po is the pressure outside soap bubble, then pressure P1 inside soap bubble is given by
P1 = [ Po + ( 4T/R) ] .................(1)
where T is surface tension and R is radius of bubble.
Volume of bubble V1 = (4/3)πR3 ................(2)
If pressure outside the bubble is reduced n-fold and diameter increaded r-fold,
then changed pressure P2 and changed volume V2 are given by,
P2 = [ ( Po /n) + ( 4T/ (r R) ) ] .........................(3)
V2 = (4/3)π r3 R3 .....................................(4)
From Boyl's law, we have, P1V1 = P2V2 ................(5)
using all the above equations, we get ,
[ Po + ( 4T/R) ] (4/3)πR3 = [ ( Po /n) + ( 4T/R) ] (4/3)π r3 R3 ....................(6)
After simplification, T = (1/4) Po R [ 1 - (r3 / n ) ] [ 1 / (r2 - 1) ]
In terms of diameter D, we get , T = (1/8) Po D [ 1 - (r3 / n ) ] [ 1 / (r2 - 1) ]
Answered by Expert
20th October 2019,
3:53 PM
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