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NEET Class neet Answered

please answer this
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Asked by Prashant DIGHE | 04 Jun, 2020, 10:11: PM
answered-by-expert Expert Answer
a right parenthesis O n space c o m p a r i n g space g i v e n space e q u a t i o n space o f space w a v e space w i t h space i d e a l space w a v e space w e space g e t y equals A C o s open parentheses k x plus omega t close parentheses equals A C o s open parentheses a x plus b t close parentheses 2 πf equals straight b straight f equals fraction numerator straight b over denominator 2 straight pi end fraction fraction numerator 2 straight pi over denominator straight lambda end fraction equals straight a straight lambda equals fraction numerator 2 straight pi over denominator straight a end fraction straight b right parenthesis The space intensity space of space the space reflected space wave space is space 0.64 straight I And space straight I space directly space proportional space to space straight A squared Therefore space straight A subscript straight R over straight A subscript straight I equals square root of straight I subscript straight R over straight I subscript straight I end root straight A subscript straight R equals straight A subscript straight I square root of fraction numerator 0.64 straight I subscript straight I over denominator straight I subscript straight I end fraction end root straight A subscript straight R equals 0.8 straight A subscript straight I And space reflected space wave space suffers space straight a space phase space change space of space straight pi straight y subscript straight r equals 0.8 ACos open parentheses ax minus bt plus straight pi close parentheses straight C right parenthesis Resultant space wave space straight y equals straight y subscript straight i plus straight y subscript straight r straight y equals 0.8 ACos open parentheses ax minus bt plus straight pi close parentheses plus ACos open parentheses ax plus bt close parentheses straight y equals negative 0.8 ACos open parentheses ax minus bt close parentheses plus ACos open parentheses ax plus bt close parentheses On space differentiatin we space get dy over dt equals negative AbSin left parenthesis ax plus bt right parenthesis plus 0.8 sin left parenthesis ax minus bt right parenthesis on space expanding space and space solving space we space get space straight v equals Ab left parenthesis 0.2 SinaxCosbt minus 1.8 CosaxSinbt right parenthesis The space magnitude space of space maximum space velocity space occurs space at space Sin space ax equals 1 space and space Cos space bt equals 1 open vertical bar straight V subscript max close vertical bar equals 1.8 Ab open vertical bar straight V subscript min close vertical bar equals 0.2 Ab
Answered by Utkarsh Lokhande | 05 Jun, 2020, 03:03: PM

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