CBSE Class 11-science Answered
Please answer this question.
Asked by dineshchem108 | 20 Sep, 2018, 08:50: AM
Expert Answer
From the given equation of a circle we can find the centre of a circle.
As diameter always passes through the centre it will satisfy equation of diameter.
x2 + y2 - 12x + 4y + 6 = 0
Comparing with ax2 + ay2 + 2gx + 2fy + c = 0
2g = -12 and 2f = 4
g = -6 and f = 2
Centre of teh circle is (-g, -f) = (6, -2)
The centre satisfy x + 3y = 0.
Option B is correct.
Answered by Sneha shidid | 20 Sep, 2018, 10:29: AM
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