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CBSE Class 12-science Answered

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Asked by dineshchem108 | 28 Apr, 2019, 11:01: PM
answered-by-expert Expert Answer
 
 
The magnitude of electric field at point P at distnace of r1 is given by Gauss's law,
 
According to Gauss's law,
 
Total electric field is,
E. dA = Q/ ε0 
 
Thus,
 
E. space left parenthesis 4 pi r subscript 1 squared right parenthesis space equals space begin inline style 1 over element of subscript 0 end style integral rho space d V
E. space left parenthesis 4 pi r subscript 1 squared right parenthesis space equals begin inline style 1 over element of subscript 0 end style integral subscript 0 superscript r subscript 1 end superscript fraction numerator Q over denominator pi R to the power of 4 end fraction r space left parenthesis 4 pi r squared right parenthesis d r
E space equals space begin inline style fraction numerator 1 over denominator 4 pi r subscript 1 squared element of subscript 0 end fraction end style space fraction numerator Q.4 pi r squared over denominator pi R to the power of 4 end fraction integral subscript 0 superscript r subscript 1 end superscript left parenthesis r cubed space d r right parenthesis space
O n space i n t e g r a t i n g space w e space g e t comma
equals space fraction numerator Q r subscript 1 superscript 2 over denominator 4 pi element of subscript 0 R to the power of 4 end fraction
Hence correct option is (C)
Answered by Shiwani Sawant | 28 Apr, 2019, 11:58: PM
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