NEET Class neet Answered
Please answer this
Asked by Prashant DIGHE | 29 Jul, 2019, 07:58: PM
Expert Answer
Figure shows the light ray parallel to axis of the mirror and at a height f from the axis, where f is focal length.
Parallel ray will pass through the focal point O and another ray from object that is passing through
focal point O will become parallel on other side of axis after reflection. If the Object is at a distance >2f from mirror,
then diminished and inverted image will be formed between f and 2f.
As per the question, we need to find the ratio, (2f-v)/f , where v is the mirror-to-image distance
It can be seen from figure, ΔOAB and ΔOCD are similar triangle, hence, CD/AB = (v-f)/f = mf/f = m .........................(1)
where m is magnification
From eqn.(1), we get, v/f = m+1 ....................(2)
hence the ratio, (2f-v)/f = 2 -(v/f) = 2-(m+1) = 1-m ....................(3)
Answered by Thiyagarajan K | 02 Aug, 2019, 02:21: PM
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