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Asked by Prashant DIGHE | 02 Jun, 2020, 09:50: PM
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A string of length 0.4m and mass 10^-2kg is clamped at both the ends. We have to calculate the time for consturctive interference nbetween the pulse.
V e l o c i t y equals square root of fraction numerator T e n s i o n over denominator m a s s space p e r space u n i t space l e n g t h end fraction end root V e l o c i t y equals square root of fraction numerator 1.6 over denominator begin display style bevelled fraction numerator 10 to the power of negative 2 end exponent over denominator 0.4 end fraction end style end fraction end root V e l o c i t y equals 8 m divided by s T h e space c o n s t r u c t i v e space i n t e r f e r e n c e space t a k e s space p l a c e space w h e n space t h e space w a v e s space a r e space i n space t h e space s a m e space p h a s e. T h e space w a v e space a f t e r space r e f l e c t i o n space f r o m space t h e space f i r s t space s u r f a c e space u n d e r g o e s space a space p h a s e space c h a n g e space o f space pi space a n d space i t space u n d e r g o e s space a space p h a s e space c h a n g e space o f space pi space space a g a i n space a f t e r r e f l e c t i o n space f r o m space t h e space s e c o n d space s u r f a c e comma space a s space b o t h space t h e space s u r f a c e s space a r e f i x e d divided by r i g i d H e n c e space t h e space w a v e space w i l l space b e space i n space t h e space s a m e space p h a s e space a f t e r space t r a v e l i n g space 2 l i. e space d i s tan c e space t r a v e l l e d equals 2 cross times 0.4 equals 0.8 m S p e e d space equals fraction numerator D i s tan c e over denominator t i m e end fraction t i m e equals fraction numerator 0.8 over denominator 8 end fraction equals 0.1 space s e c o n d s
Answered by Utkarsh Lokhande | 03 Jun, 2020, 07:46: AM

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