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please answer this

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Asked by Prashant DIGHE 14th January 2020, 10:11 PM
Answered by Expert
Answer:
Half life of radioactive element = 20 min ;  decay constant  λ = ( ln2 ) /20  ≈ 0.0347 min-1
 
Let after t1 seconds, 33% is disintegrated , hence we have  0.67 = e-λ × t1  .........................(1)
 
Let after t2 seconds, 67% is disintegrated , hence we have  0.33 = e-λ × t2  .........................(2)
 
 
By dividing eqn.(2) with eqn.(1),  we get, e-λ × ( t2 - t1 ) = 0.33 / 0.67 ≈ 0.5
 
Hence ,  λ ( t2 - t1 ) = ln2    or  (t2-t1) = (ln2 ) / λ = ( ln2 ) /0.0347 ≈ 20 min
Answered by Expert 15th January 2020, 8:02 AM
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