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Asked by Prashant DIGHE | 11 Jun, 2020, 10:09: PM
answered-by-expert Expert Answer
(a) Concentration of HCl and acetic acid after mixing=0.1M
Acetic acid is dissociated as-
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space CH subscript 3 COOH left right double arrow CH subscript 3 COO to the power of minus space plus space straight H to the power of plus
At space straight t equals 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0.1 space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space 0.1 left parenthesis From space HCl right parenthesis
At space straight t equals equilibrium space space space space space space space space space space space space space space space space space 0.1 minus straight x space space space space space space space space space space space straight x space space space space space space space space space space space space space space space space space space 0.1 plus straight x


straight K subscript straight a equals fraction numerator left parenthesis 0.1 plus straight x right parenthesis over denominator left parenthesis 0.1 minus straight x right parenthesis straight x end fraction
1.75 cross times 10 to the power of negative 5 end exponent equals fraction numerator straight x left parenthesis 0.1 plus straight x right parenthesis over denominator left parenthesis 0.1 minus straight x right parenthesis end fraction

straight x almost equal to 1.75 cross times 10 to the power of negative 5 end exponent
left square bracket straight H to the power of plus right square bracket equals 0.1 plus straight x almost equal to 0.1 straight M
pH equals negative log left square bracket 0.1 right square bracket equals 1

Degreee space of space dissociation space of space acetic space acid equals fraction numerator 1.75 cross times 10 to the power of negative 5 end exponent over denominator 0.1 end fraction equals 1.75 cross times 10 to the power of negative 4 end exponent
(b)
N u m b e r space o f space m o l e s space o f space N a O H space a d d e d equals 6 over 40 equals 0.15
space space space space space space space space space space space space space space space space space space space space space space CH subscript 3 COOH space plus thin space HCl space plus space NaOH space left right double arrow CH subscript 3 COONa space plus space NaCl space plus space straight H subscript 2 straight O
space space straight t equals 0 space space space space space space space space space space space space space space space 0.1 space space space space space space space space space space space space space space space 0.1 space space space space space 0.15 space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space 0
straight t equals equilibrium space space space 0.05 space space space space space space space space space space space space space 0 space space space space space space space space space space space 0 space space space space space space space space space space space space space 0.05 space space space space space space space space space space space space space space 0.1 space space space space space space space space space 0

pH equals pK subscript straight a space plus space log fraction numerator left square bracket Salt right square bracket over denominator left square bracket Acid right square bracket end fraction
pH equals negative log left parenthesis 1.75 cross times 10 to the power of negative 5 end exponent right parenthesis space plus log fraction numerator 0.05 over denominator 0.05 end fraction equals 4.757
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