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please answer this

 

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Asked by Prashant DIGHE 6th December 2019, 10:29 PM
Answered by Expert
Answer:
if the conductor has jumped to a height h, then its initial velocity v from its resting position is given by
 
v = (2gh)1/2 ....................(1)
 
impulse due to force acting on conductor = F dt = d(mv) = (mv-0)= mv  ...............(2)
 
force F acting on conductor in magnetic field is given by,  F = B i l ................(3)
 
where B is magnetic field flux density, i is current passing through the conductor and l is length of conductor
 
impulse = F dt = ( B i l ) dt = B l q ......................(4)
 
where q = ( i dt )  is the charge passed to the conductor
 
from eqn.(2) and (4), we get,  mv = B l q    or   q = (m v ) / ( B l ) .........................(5)
 
Using eqn.(1), we get, q = [ m (2gh)1/2 ] / ( B l )
Answered by Expert 7th December 2019, 12:19 PM
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