NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 07 Dec, 2019, 10:19: PM
Expert Answer
Figure shows a rod of length L pivoted at O rotating with frequency f .
Let the charge q is distrubuted uniformly in the rod so that it has linear charge density λ per unit length.
Let us consider a small element ds having charge λds at a distance s from O.
Due to rotation of rod, this small charged element λds makes a current loop of area πs2
Current passing in the loop = charge per second = λds × f
Magnetic moment dm of this loop is given by, dm = current × area = λds × f × ( πs2 )
Magnetic moment m due to rotation of rod is given as
.................................(1)By substituting λL = q , we get magnetic moment m = π q f (L2 / 3 )
Answered by Thiyagarajan K | 07 Dec, 2019, 11:54: PM
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