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CBSE Class 11-science Answered

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Asked by Prashant DIGHE | 22 Apr, 2020, 10:48: PM
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when train starts from rest , moves with uniform acceleration a and attains maximum speed v , then we have
 
v2 = 2 a S1 ......................(1)
 
time taken t to attain maximum speed ,  t1 = v/a  ....................(2)
 
where S1 is distance travelled
 
After attaining maximum speed , moves with retardation a and comes to rest after travelling a distance S2 .
 
Then we have,  v2 = 2 a S2...............(3)
 
time taken t to come to rest ,  t2 = v/a  ...................(4)
 
Total distance travelled ,  S = S1 + S2 = ( v2 / 2a ) + ( v2 / 2a ) = ( v2 / a ) ................(5)
 
Total time travelled , t = t1 + t2 = (2v)/a    .................. (6)
 
using eqn.(5), we rewrite eqn.(6) as ,  begin mathsize 14px style t space equals space 2 space square root of S over a end root end style
maximum speed , begin mathsize 14px style v space equals space square root of a space S end root end style
Answered by Thiyagarajan K | 23 Apr, 2020, 08:47: AM
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CBSE 11-science - Physics
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