NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 03 Mar, 2020, 10:00: PM
Expert Answer
Option (2) is correct.
Given:
For bulb A,
Volume, VA = 100 ml
Pressure, =PA
For Bulb B,
Volume, =VB
Pressure, PB =
Using Boyle's law,
PAVA = PBVB
PA × 100 = × VB
VB =
VB = 250 ml
Before opening stopcock, volume of gas in bulb B must be (250-100) = 150 ml
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