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please answer this

Asked by Prashant DIGHE 10th April 2020, 9:40 PM
Answered by Expert
Magnetic field at centre of circular loop = μo i / (2R) , where R is radius of circular loop , i is the current passing in the loop
and μo is the permeability of free space .
Given circular coil has one and half turns. Hence magnetic field B at centre of coil is given by,
B =  (3/2)×μo i / (2R) = (3/4)μo i / R  .......................(1)
Current i in the coil is given as,  i = V/r  , where V is EMF of battery and r is the resistance coneected in the circuit.
After substituting for current, eqn.(1) becomes ,  B = (3/4)μo V / ( R r )
Answered by Expert 11th April 2020, 8:09 AM
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