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Please answer this

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Asked by Prashant DIGHE 9th October 2019, 10:03 PM
Answered by Expert
Answer:
when the container moves down on the inclined plane, acceleration of the container is ( g sinθ ) .
 
Since the container is accelerated downwards, backside of liquid level is greater than front side of liquid level.
 
pressure difference between backside and frontside ≈ ρ g ( h1 - h2 ) cosθ ............(1)
 
If this pressure difference given above is due to acceleration,  then we get,  ρ g ( h1 - h2 ) cosθ = ( ρ L g sinθ )  ..............(2)
 
Hence from eqn.(2), slope of the free surface,  [ ( h1 - h2 )/L ] = tanθ
 
Answered by Expert 14th October 2019, 8:58 AM
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