NEET Class neet Answered
Please answer this
Asked by Prashant DIGHE | 09 Oct, 2019, 10:03: PM
Expert Answer
when the container moves down on the inclined plane, acceleration of the container is ( g sinθ ) .
Since the container is accelerated downwards, backside of liquid level is greater than front side of liquid level.
pressure difference between backside and frontside ≈ ρ g ( h1 - h2 ) cosθ ............(1)
If this pressure difference given above is due to acceleration, then we get, ρ g ( h1 - h2 ) cosθ = ( ρ L g sinθ ) ..............(2)
Hence from eqn.(2), slope of the free surface, [ ( h1 - h2 )/L ] = tanθ
Answered by Thiyagarajan K | 14 Oct, 2019, 08:58: AM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
