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Please answer this

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Asked by Prashant DIGHE 8th October 2019, 9:42 PM
Answered by Expert
Answer:
Let Pa is atmospheric pressure
 
density of liquid d2 is twice of mercury density 13.6 g/cm3
 
Pressure P1 = Pa + 2×(25 cm of mercury pressure)
 
density of liquid d1 is mercury density 13.6 g/cm3
 
Pressure P2 = P1 + 26 cm of mercury pressure = Pa + 76 cm of mercury pressure
 
since atmospheric pressure Pa is 76 cm of mercury pressure,  we get pressure at closed limb of u-tube,  p = 2 Pa
Answered by Expert 9th October 2019, 10:16 AM
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