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please answer this

Asked by Prashant DIGHE | 26 Apr, 2020, 09:43: PM

Expert Answer

A particle is projected from tower as given in the figure.

To find: - Distance from the foot of the tower where it will strike the ground.

W e space k n o w comma space s space equals space u t space plus space 1 half space a t squared space H e r e comma space u subscript y space equals space u space sin theta space equals space u space sin space 37 degree space sin space 37 degree space equals space 0.6 space T h u s comma space u subscript y space equals fraction numerator space 500 over denominator 3 end fraction cross times 0.6 space equals space 100 space A s space t h e space p a r t i c l e space i s space f a l l i n g space i n space d o w n w a r d space d i r e c t i o n comma space minus 1500 space equals space minus space 100 space t space plus 1 half space left parenthesis negative 10 right parenthesis t squared 1500 space equals space 100 space t space plus 1 half space left parenthesis 10 right parenthesis t squared space space equals space 100 space t space plus space 5 t squared space 300 space equals space 20 t space plus space t squared space T h u s comma space space t space equals space minus 30 space s space a n d space t space equals space plus 10 space s T i m e space c a n n o t space b e space n e g a t i v e comma S o comma space s u b s t i t u t i n g space t space equals space 10 space s space i n space H o r i z o n t a l space d i s tan c e space f r o m space t h e space f o o t space o f space t o w e r space i s space equals open parentheses space u cos theta close parentheses space t cos space 37 degree space equals space 0.8 space rightwards double arrow space H o r i z o n t a l space d i s tan c e space equals space 500 over 3 cross times 0.8 space cross times space 10 space equals space 4000 over 3 space m space

No option given in question matches the answer.

Answered by Shiwani Sawant | 27 Apr, 2020, 05:09: PM

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