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please answer this

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Asked by Prashant DIGHE 24th April 2020, 10:10 PM
Answered by Expert
Answer:
when engine is on , rocket moves up with uniform velocity v for time to so that vertical distance ho
moved with uniform speed is  ( v to ) .
 
After time to , engine is off, hence rocket will move with initial speed v in gravitaional field  and
travels some vertical distance till its speed comes to zero.
 
Vertical distance travelled by rocket when engine is off ,  h  = (v2 / 2g )
 
Hence total height reached by rocket = ho + h  = v to + [ v2 / (2g) ]
Answered by Expert 25th April 2020, 8:38 AM
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