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Asked by Prashant DIGHE | 29 Jan, 2020, 10:22: PM
answered-by-expert Expert Answer
Workdone by adiabatic process W is given by
begin mathsize 14px style W space equals fraction numerator P subscript i V subscript i superscript gamma over denominator 1 minus gamma end fraction space space open parentheses V subscript f superscript 1 minus gamma end superscript space minus space V subscript i superscript 1 minus gamma end superscript close parentheses end style
where Pi is initial pressure, Vi is initial volume, Vf is final volume and γ is adiabatic constant
 
we have initial pressure at STP, Pi = 1.013 × 105 Pa , initial volume Vi = 1 litre = 10-3 m3
and final volume Vf = 3 litre = 3 × 10-3 m3
 
Workdone W = [ 1.013 × 105 × (10-3 )γ / (-0.4) ] × [ 3-0.4 - 1 ] × (10-3)1-γ
 
W = [ 101.3 / (-0.4)] ×[ 3-0.4 - 1 ] = 90 J
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