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# Please answer this

Asked by Prashant DIGHE 8th October 2019, 9:41 PM
Answered by Expert
Answer:
Pressure at B, at half of depth of lake, PB = 10ρg  ................(1)
where ρ is density of water.

If pressure PC at water is 4/3 times of PB , then PC = (40/3)ρg  ...............(2)

pressure difference , PC - PB = ρg (h/2) = [ (40/3) - 10 ] ρg ..................(3)
where h is depth of lake

from eqn.(3) we get,  h = (20/3) m  =  6.67 m
Answered by Expert 9th October 2019, 9:49 AM
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