Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (North)

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

8788563422

Mon to Sat - 10 AM to 7 PM

Please answer the following question with explanation 

qsnImg
Asked by deepakudgiri29 28th November 2018, 5:36 PM
Answered by Expert
Answer:
2N2O5 4NO2 O2
    P            0                          0
(P-x) 2x x/2
   0 2P P/2
 
Total Pressure after complete dissociation 
 
5P/2 = 584.5
 
Pt = 233.8mmHg
 
Applying 1st order equation we have
 
K = 2.303/30 log [P]/[P-x]
 
= 2.303/30 log233.8/200
= 0.07log 1.16
 
~ 5×10-3
 
{ for calculation of "x" }
 
P-x+2x+x/2 = 284.5
 
x = 284.5 - 233.8 = 33.8 mmHg 
Answered by Expert 6th December 2018, 2:22 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp