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Home / Doubts and Solutions/JEE/Chemistry

Please answer the following question with explanation

qsnImg
Asked by Deepak 10th September 2018, 2:39 PM
Answered by Expert
Answer:
Initially, mass of H2SO4 solution = 1.294× 3.5 ×1000 g
 
                                                = 4.529 kg
 
Weight space of space straight H subscript 2 SO subscript 4 space equals 39 over 100 cross times 4.529 space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1.7663 space kg Moles space of space straight H subscript 2 SO subscript 4 space equals fraction numerator 1.7663 over denominator 98 end fraction cross times 1000 space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 18.02 space mol left square bracket straight H subscript 2 SO subscript 4 right square bracket space equals space 5.15 space straight M Finally comma space mass space of space straight H subscript 2 SO subscript 4 space solution space equals space 1.139 space cross times 3.5 space kg space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3.9865 space kg Mass space of space straight H subscript 2 SO subscript 4 space equals space 20 over 100 cross times 3.9865 space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.7973 space kg Moles space of space space straight H subscript 2 SO subscript 4 space equals fraction numerator 0.7973 over denominator 98 end fraction cross times 1000 space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 8.136 space mol left square bracket space straight H subscript 2 SO subscript 4 right square bracket space equals 2.324 space straight M Moles space of space space straight H subscript 2 SO subscript 4 space consumed space duering space discharge space equals 18.02 space minus 8.136 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 9.887 space moles 2 space moles space of space space space straight H subscript 2 SO subscript 4 space equals space 2 cross times 96500 9.887 space mol space of space space straight H subscript 2 SO subscript 4 space equals space fraction numerator 2 cross times 96500 cross times 9.887 over denominator 2 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 954095.5 space straight C As space 3600 space straight C space equals space 1 space amp. hr therefore space space 954095.5 space straight C space space equals space fraction numerator space 954095.5 space over denominator 3600 end fraction space space space space space space space space space space space space space space space space space space space space space space space space equals space 265 space amp. hr.
 
265 amp.hr battery was used.
Answered by Expert 11th September 2018, 12:26 PM
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