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Please answer the following question with explanation

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Asked by deepakudgiri29 14th December 2018, 5:09 PM
Answered by Expert
Answer:
Multiple bond do not allow for free rotation so, larger time the compound makes itself stable in single bond, more free rotation is observed.
 
Structures i and ii will have dipole moments since due to the charge isolation the two rings are stable since they follow huckels rule of aromaticity, so single bond is in these two structure but same is not observed in the iii structure so it will remain in double bond. For charge separation refer the image attached.
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Answered by Expert 15th December 2018, 10:17 AM
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