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Please answer the following question with explanation

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Asked by Deepak 12th September 2018, 10:07 PM
Answered by Expert
Answer:
When switch-1 is closed, inductor is connected to battery of emf E through a resistance R.
 
Energy W stored in Inductor is given by,  W = (1/2)L×i2 .............(1)
 
L is inductance and i is the current passing through inductance at steady state.
 
Assuming inductor has negligible resstance, we have,   i = E/R2  ................(2)
 
from (1) and (2), we write,   begin mathsize 12px style W space equals space 1 half cross times L cross times open parentheses E over R subscript 2 close parentheses squared space space space equals space fraction numerator L cross times E squared over denominator 2 cross times R subscript 2 superscript 2 end fraction end style...................(3)
when switch-2 is closed, stored energy as given in (3) is dissipated in Resistor R1
Answered by Expert 13th September 2018, 10:35 AM
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