CBSE Class 9 Answered
Please answer the foll:question
Asked by ashwati | 08 Mar, 2009, 06:07: PM
Expert Answer
Let the point of intersection of DF and AE be G.(say)
D and F are given as midpoints of AB and AC.
So DF is parallel to BC and half of it (mid point thm)
Now consider triangle ABE.
D is the mid point of AB and DG parallel to BE.
So,
So G must be the mid point of AE( converse of mid point thm)
i.e.
So we can say that DF bisects AE.
Next,
E is the mid point of BCand G is the mid point of AE.
So,DG=1/2(BE)=1/4(BC)
Simly,
GF=1/4(BC)
So,
DG=GF
So,
AE bisects DF
Thus we have proved that
AE and DF bisect each other.
Answered by | 08 Mar, 2009, 07:56: PM
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