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CBSE Class 11-science Answered

Please answer question number 2 .
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Asked by arunavamitra50 | 27 Jun, 2018, 05:05: PM
answered-by-expert Expert Answer
Given velocity function,  begin mathsize 12px style V left parenthesis t right parenthesis space equals space fraction numerator d over denominator d t end fraction r left parenthesis t right parenthesis space equals space left parenthesis 12 minus 6 t right parenthesis i with rightwards arrow on top plus space 4 j with rightwards arrow on top space............ left parenthesis 1 right parenthesis
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where r(t) is position vector as a function of time. r(t) will be obtained by integrating eqn.(1)
 
begin mathsize 12px style r left parenthesis t right parenthesis space equals space open parentheses 12 t space minus space 3 t squared close parentheses space i with rightwards arrow on top space plus space 4 t space j with rightwards arrow on top space........ left parenthesis 2 right parenthesis
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From eqn.(2), we can say x-component is zero, when t = 4 s. Hence y-coord = 4×4 = 16 m
Answered by Thiyagarajan K | 28 Jun, 2018, 11:57: AM
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