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Please answer it. 

Asked by amitjena226 25th November 2017, 2:22 PM
Answered by Expert
Answer:
 
 
f o r m space t h e space e q u a t i o n space o f space p h o t o e l e c t r i c space e f f e c t

fraction numerator h c over denominator lambda end fraction minus ϕ equals e V space
V equals fraction numerator h c over denominator e lambda end fraction minus ϕ over e space


fraction numerator ϕ 1 over denominator e end fraction equals 0.001 space f o r space m e t a l space 1

fraction numerator ϕ 2 over denominator e end fraction equals 0.002 space space f o r space m e t a l space 2

fraction numerator ϕ 3 over denominator e end fraction equals 0.004 space space f o r space m e t a l space 3 space space space

ϕ 1 colon ϕ 2 colon ϕ 3 equals 1 colon 2 colon 4

f o r space m e t a l space 2 comma
r e q u i r e d space t h r e s h o l d space w a v e l e n g t h
lambda 2 equals fraction numerator h c over denominator ϕ 2 end fraction equals fraction numerator h c over denominator 0.002 h c end fraction equals 1000 divided by 2 equals 500 space n m

f o r space m e t a l space 3
r e q u i r e d space t h r e s h o l d space w a v e l e n g t h


lambda 3 equals fraction numerator h c over denominator ϕ 3 end fraction equals fraction numerator h c over denominator 0.004 h c end fraction equals 250 space n m


w a v e l e n g t h space f o r space v i o l e t space i s space 400 n m space

e m i s s i o n space f r o m space m e t a l space 2 space i s space p o s s i b l e space b u t space n o t space f r o m space m e t a l space 3

t h e r e f o r e space o p t i o n space 1 left parenthesis i comma i i i right parenthesis
Answered by Expert 27th November 2017, 3:10 PM
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