Pl. answer my question urgently
Asked by
10th March 2010,
10:18 AM
Answered by Expert
Answer:
ATQ,
when p(x) is divided by x-2, it leaves a rem of 1
so we get
p(x)=(x-2)q(x)+1...(i)
next it's given that when p(x) is divided by x-3 rem is 3
i.e.
p(3)=3
substituting in (i) we get
p(3)=[1 x q(3)]+1
but p(3)=3
so
3=q(3)+1
so
q(3)=2
i.e. when q(x) is divided by x-3 it leaves a rem of 2
i.e.
q(x)=[(x-3)r(x)]+2... where r(x) is (say) the quotient
so substituting this value of q(x) in (i) we get,
p(x)=[(x-2)q(x)]+1
=([(x-2){(x-3)r(x)+2})+1
=[(x-2)(x-3)r(x)]+[2(x-2)]+1
so
p(x)=(x-2)(x-3)[r(x)]+[2x-4+1]
so the reqd rem is 2x-4+1=2x-3
Answered by Expert
10th March 2010,
4:35 PM
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