NEET Class neet Answered
phy
Asked by anushkagoyal656 | 28 Apr, 2022, 05:18: PM
Expert Answer
Let m be mass of bullet moving with initial speed u.
Total initial momentum = m u
After penetrating wooden block , let the bullet move with speed v . Due to collision, wooden block moves with speed V just after collision.
Final momentum just after collision = ( M V ) + ( m v )
where M is mass of wooden block
Since momentum is conserved , we have
m u = ( M V ) + ( m v )
after simplification , we get , v = u - (M/m) V ..................(1)
After collision , centre of mass of wooden block is raised 10 cm upwards
Hence by energy conservation , (1/2) M V2 = ( M g h )
Hence speed of wooden block just after collision , V = 
..................(2)
..................(2)Using eqn.(2) , we rewrite eqn.(1) as
v = u - ( M / m )
v = 400 - ( 2 /.01 ) 
v = 120 m/s
Answered by Thiyagarajan K | 28 Apr, 2022, 05:52: PM
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