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CBSE Class 12-science Answered

Photoelectric work function of metal is 1eV. Light of wavelength 3000 A falls on it. What is the velocity of the ejected photo electron?
Asked by rutujasarangmehta | 15 Mar, 2016, 06:39: PM
answered-by-expert Expert Answer
begin mathsize 14px style Energy space of space incident space light space equals hc over straight lambda
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 6.62 cross times 10 to the power of negative 34 end exponent cross times 3 cross times 10 to the power of 8 over denominator 3000 cross times 10 to the power of negative 10 end exponent end fraction equals 6.62 cross times 10 to the power of negative 19 end exponent space straight J
therefore hv equals straight ϕ subscript 0 plus 1 half mv squared
hc over straight lambda equals straight ϕ subscript 0 plus 1 half mv squared
1 half mv squared equals hc over straight lambda minus straight ϕ subscript 0
space space space space space space space space space space space equals 6.62 cross times 10 to the power of negative 19 end exponent minus 1 cross times 1.6 cross times 10 to the power of negative 19 end exponent
space space space space space space space space space space space equals 5.02 cross times 10 to the power of negative 19 end exponent
straight v squared equals fraction numerator 5.02 cross times 10 to the power of negative 19 end exponent cross times 2 over denominator 9.1 cross times 10 to the power of negative 31 end exponent end fraction equals 1.1 cross times 10 to the power of 12
straight v equals 10 to the power of 6 space straight m divided by straight s
therefore The space velocity space of space the space ejected space photo space electron space is space 10 to the power of 6 space straight m divided by straight s. end style
Answered by Faiza Lambe | 16 Mar, 2016, 11:03: AM
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