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P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that:

ar(APB) = ar(BQC)

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

Since APB and ||gm ABCD are on the same base AB and between the same parallels AB and DC

ar(APB) = ....(i)

Similarly ar(BQC) = ...(ii)

From (i) and (ii) we have

Answered by Expert 4th June 2014, 3:23 PM
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