P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that:
ar(APB) = ar(
BQC)
Since APB and ||gm ABCD are on the same base AB
and between the same parallels AB and DC
ar(
APB) =
....(i)
Similarly ar(BQC) =
...(ii)
From (i) and (ii) we have
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