P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that:
ar(
APB) = ar(BQC)
Asked by Topperlearning User
4th June 2014,
1:23 PM
Answered by Expert
Answer:
Since APB and ||gm ABCD are on the same base AB
and between the same parallels AB and DC
ar(APB) = 
....(i)
Similarly ar(BQC) = ...(ii)
From (i) and (ii) we have
Answered by Expert
4th June 2014,
3:23 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Number System
- 2 Polynomials
- 3 Coordinate Geometry
- 4 Linear Equations in Two Variables
- 5 Introduction to Euclid's Geometry
- 6 Heron's Formula
- 7 Surface Areas and Volumes
- 8 Statistics
- 9 Probability
- 10 Lines and Angles
- 11 Triangles
- 12 Quadrilaterals
- 13 Areas of Parallelograms and Triangles
- 14 Circles
- 15 Geometric Constructions
Trending Tags
Latest Questions
CBSE XI Science Physics
Asked by bullurebaswaraj
16th December 2018,
11:24 PM
ICSE IX Mathematics
Asked by prashanth.rajappa
16th December 2018,
11:16 PM
CBSE XII Science Chemistry
Asked by ranvirsingh1as
16th December 2018,
10:51 PM
