CBSE Class 12-science Answered
Oxidation state of 'v' in
Rb4Na [HV10O28] is :-
Asked by Atulcaald | 18 May, 2018, 01:23: AM
Expert Answer
Let the O.S. of V is x
The charge is 0 of complex
Therefore,
4(1) +1 +1 + 10x + (2) 28 = 0
6 + 10x + 56= 0
10x = 50
x=5
The oxidation state of 'v' in Rb4Na [HV10O28] is:- +5
Answered by Ramandeep | 18 May, 2018, 11:17: AM
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