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On selfing a plant of F1- generation with genotype "AABbCC", the genotypic ratio in F2- generation will be:[Please explain the cross in detail] (a)3:1 (b)1:1 (c)9:3:3:1 (d)27:9:9:9:3:3:3:1
Asked by Balbir | 30 Dec, 2019, 09:57: PM
answered-by-expert Expert Answer

Selfing is the process of fertilization with polar or male gametes of the same individual.

AABbCC will produce two type of gametes ABC and AbC. 

Since, AABbCC contains only one heterozygous allelic pair 'Bb', the cross would behave as a monohybrid cross leading to 3 : 1 phenotypic ratio in F2 generation.

F1 generation – AABbCC × AABbCC

Gametes – ABC and AbC

Sellfing-

 

ABC

AbC

ABC

AABBCC

AABbCC

AbC

AABbCC

AAbbCC

Phenotypic ratio = 3 : 1

Genotypic ratio = AABBCC : AABbCC : AAbbCC = 1 : 2 : 1

Answered by Sheetal Kolte | 31 Dec, 2019, 01:16: PM

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