CBSE Class 12-science Answered
Of all the closed cylindrical cans, which enclose a given volume has the minimum surface area?
Asked by | 07 Sep, 2009, 01:09: PM
Expert Answer
Given volume = V
πr2h = V
h = V/πr2
S = total surface area = 2πr2 + 2πrh
= 2πr2 + 2πr(V/πr2)
= 2πr2 + 2V/r
To minimize the surface area,
dS/dr = 4πr - 2V/r2 = 0
d2S/dr2 = 4π + 4V/r3 > 0
2πr = V/r2
r = (V/2π)1/3
r = (100/2π)1/3
r = 2.52 cm and h = 5.02 cm.
The cylindrical can with r = 2.52 cm and h = 5.02 cm, will minimize the total surface area.
Regards,
Team,
TopperLearning.
Answered by | 07 Sep, 2009, 01:44: PM
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