Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Of all the closed cylindrical cans, which enclose a given volume has the minimum surface area?
Asked by | 07 Sep, 2009, 01:09: PM
answered-by-expert Expert Answer

Given volume = V

πr2h = V

h = V/πr2

S = total surface area = 2πr2 + 2πrh

= 2πr2 + 2πr(V/πr2)

 = 2πr2 + 2V/r

To minimize the surface area,

dS/dr = 4πr - 2V/r2 = 0

d2S/dr2 = 4π + 4V/r3 > 0  

2πr = V/r2

r = (V/2π)1/3 

r = (100/2π)1/3 

r = 2.52 cm and h = 5.02 cm.

The cylindrical can with r = 2.52 cm and h = 5.02 cm, will minimize the total surface area.

Regards,

Team,

TopperLearning.

Answered by | 07 Sep, 2009, 01:44: PM
CBSE 12-science - Maths
Asked by mahammadsharifdakhani67 | 16 Apr, 2024, 07:43: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by 20muskaansharma23 | 08 Apr, 2024, 11:31: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by klmn445 | 03 Apr, 2024, 11:33: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by cherrycharishma512 | 01 Apr, 2024, 12:32: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by shirishakuruva477 | 28 Mar, 2024, 09:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by sheensvlog | 27 Mar, 2024, 10:15: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by jprathamesh023 | 23 Mar, 2024, 04:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by antra1799 | 18 Mar, 2024, 07:49: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×